(a) Time at which the bus and car met
=
0800 + [810 / ( 50 + 85 )]
=
0800 + 6 h
=
1400
(b) Distance covered by the bus when it met
the car
=
50 x 6
=
300 km
(c) (i) Speed which the car must travel to
reach Town T at 1630 = 300 / ( 1630 - 1400 )
=
300 / 
h
=
300 x 
h
=
120 km/h
(ii) Average Speed
of the Car
=
810 km / 8 h
=
101.25 km/h
) + (120 x 
)
=
595 + 300
=
895 km
km/h
=
68
km/h